6y^2-28y=48

Solution for 6y^2-28y=48 equation:

6y^2-28y=48

We move all terms to the left:

6y^2-28y-(48)=0

a = 6; b = -28; c = -48;
Δ = b2-4ac
Δ = -282-4·6·(-48)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-44}{2*6}=\frac{-16}{12}
=-1+1/3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+44}{2*6}=\frac{72}{12}
=6
$